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вернуться в форумfor anyone who wants to solve this problem: Послано Koala 10 сен 2003 07:51 Maybe the format of input is not: number_number. ("_"represent a
space) So please read it one character by another. And i'll share you the procedure of reading datas. Послано Koala 10 сен 2003 07:53 readln(n);
fillchar(a,sizeof(a),0);
fillchar(b,sizeof(b),0);
while true do
begin
read(ch); while ch=' ' do read(ch);
if ch='B' then
begin
readln;
break;
end;
x:=0;
while ch<>' ' do
begin
x:=x*10+ord(ch)-ord('0');
read(ch);
end;
readln(y);
insert(a[x],y); insert(b[y],x);
end; Re: And i'll share you the procedure of reading datas. Maybe you are right !
I change my reading procedure (not like you) and I
got AC Thank you!I got AC. Послано Y.Y.M. 14 июн 2004 19:40 At first,I used String to read data.
But I WA on text#1.
Finally,I realized that the input formal is like this:
number_number_.There may be some '_' after the second number.
I improve my program and got AC. That's right. The second line in sample input #2 has a space at the end of line. But(+) But you don't need to read character by character. You read a string, then delete all the spaces at its end, and you'll get AC. |
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