Обсуждение @ 1075. Нитка в пространстве @ Timus Online Judge

here is the trick!

Послано gush(gu_shenhua@yahoo.com.cn) 28 июл 2003 22:00

this may be true: 1.000 > 1.
so add this func:
    double acos1(double x)
    {
        if(x > 1)
          x = 1;
        if(x < -1)
          x = -1;
        return acos(x);
    }

Re: here is the trick!

Послано Fly [Yaroslavl_SU] 29 сен 2005 00:47

BIG thanks!!!

Re: here is the trick!

Послано Zhihua Lai 29 май 2007 22:50

Big thanks, god, without that, my program was stopped at test 8.

Re: here is the trick!

Послано Denis Koshman 3 авг 2008 11:33

It's actually 1.00000000000000001, not 1.000

BTW, same stuff should be applied to 'sqrt'. if(v<0 && v>-eps) v = 0; sqrt(v);

Re: here is the trick!

Послано Oracle[Lviv NU] 9 янв 2009 00:22

THANKS!!!!!!!!!!
It really helped me! After small fix - AC :)

Re: here is the trick!

Послано Enzo 10 июн 2010 08:10

thanks so much, i got ac with your func...

Re: here is the trick!

Послано MishaRash 31 июл 2015 13:15

Thank you very much! I had WA 24, "safe" acos didn't help, but "safe" sqrt did, I got AC. I used it so:
double sqrt1(double a) {
if (a<0)
return 0;
return sqrt(a);
}

Edited by author 31.07.2015 13:17

Re: here is the trick!

Послано Tbilsu_Irakli Khomeriki 17 сен 2018 20:09

thanks a lot, never would have figured out :)

Обсуждение задачи 1075. Нитка в пространстве