#include <stdio.h>

int main()
{
    char str[10010],output[80];
    int i,index=0;
    gets(str);
    for(i=0;i<80;i++)    output[i]=' ';

    for(i=0;str[i];i++){
        if((str[i]=='<')&&(index>0))    index--;
        else if(str[i]=='>')        index=
(index+1)%80;
        else{
            output[index]=str[i];
            index=(index+1)%80;
        }
    }
    for(i=0;i<80;i++)    printf("%c",output[i]);
    return 0;
}

You have to output the screen to the maximal sign you've read -> I
mean if u've reached only the 20th position in your array u are to
output only 20 signs .
Good luck !

> You have to output the screen to the maximal sign you've read -> I
> mean if u've reached only the 20th position in your array u are to
> output only 20 signs .
> Good luck !
No, you are wrong! In my AC solution I output 80 symbols everytime!

you program's output is wrong:
<Look for second hamburger at computer and chairs.790