l1=[]
l2=[]
l3=[]
for i in range(0,1000):
    l3.append(False)
def funct(a):
    b=a.split()
    if b[0]=='register':
        if b[1] not in l1:
            l1.append(b[1])
            l2.append(b[2])
            print("success: new user added")
        else:
            print("fail: user already exists")
    elif b[0]=="login":
        if b[1] not in l1:
            print("fail: no such user")
        else:
            k=l1.index(b[1])
            if l3[k]:
                print("fail: already logged in")
            else:
                if l2[k]==b[2]:
                    l3[k]=True
                    print("success: user logged in")
                else:
                    print("fail: incorrect password")
    elif b[0]=="logout":
        k=l1.index(b[1])
        if l3[k]:
            l3[k]=False
            print("success: user logged out")
        else:
            print("fail: already logged out")
f=int(input())
for m in range(0,f):
    n=input()
    funct(n)





f**king time limit!!!

List is O(n) lookup, while dict is O(log n), so use that