Issue resolved, see below!

Edited by author 27.01.2015 05:49

So, be careful if manually calculating - subtle fact is that the aggregate majority of a sequence of numbers may not actually represent the majority from each individual group, for example (from another thread):

5
5 5 5 5 5
=> 9

But at first, I naively calculated (5+5+5)/2 + 1, which works in other group sizes but not for duplicate numbers. So, just keep that in mind :)

Edited by author 27.01.2015 05:49