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вернуться в форумEasy solution We can just rotate our second diamond and compare it to the first diamond. Like this: for(int i=0;i<4;i++) {for(int j=0;j<3;j++) {if(a==b) {cout<<"equal"<<endl;return 0;} // Rotate diamond around current base-face string x=e+b[2]+b[3]+b[1]; b=b[0]+x;} string t="abcd"; // Change base-face if(i!=2) {t[0]=b[1];t[1]=b[3]; t[2]=b[2];t[3]=b[0];} else {t[0]=b[2];t[1]=b[1]; t[2]=b[3];t[3]=b[0];} b=t;} |
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