Hi All,

1. 1st player Take 2 stones   left over is 8-2=6
2. 2nd player  takes 1 stone  left over  is 6-1=5
3. 1st player takes either 1 (left over is 4)0r 4 stones (left over is 1)
4. Finally 2nd player takes remiang stones.  Thus second player wins.

Did I understand the problem statements properly? According to the output given in sample 1st player has won but how? Please could you explain.

Regards
Anupam

Now I got it, in 3rd step player picks up 2 stones. Then it guarnatees win of 1st player.