#include <stdio.h>
#include<string.h>

int main()
{
    int sel[10010],n,m,tmp,i;
    scanf("%d%d",&n,&m);

    memset(sel,0,10010*sizeof(int));

    for(i=0; i<m; i++) {
        scanf("%d",&tmp);
        sel[tmp]++;
    }

    for(i=1; i<=n; i++)
        printf("%.2f%\n",((double)sel[i]*(double)100)/(double)m);

    return 0;
}

whats wrong?

        printf("%.2f%%\n",
problem is here. it needs two %

Why it needs 2 of '%'?

% should also be printed at the end, I just found this mistake :)

I am also amazed by this.
My code is working in ideone with single "%".
http://ideone.com/cbm8uh



Edited by author 03.01.2015 15:49