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back to boardCombinatorial Can anybody explain the combinatorial approach of this problem ??? Greetings Re: Combinatorial Posted by hatred 9 Jul 2011 21:29 the solution is very simple, combinatory isn't needed ;) Re: Combinatorial I think it is coz brute force would be a good pain in ass with n > 9. But if u find a general solution with combinatorics it would be very efficient. I could not find one, though. |
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