#include <stdio.h>
int main()
{
    int n1,c1,n2,t,c2,n3,k,i;
    scanf("%d %d",&n1,&c1);
    scanf("%d %d %d",&n2,&t,&c2);
    scanf("%d",&n3);
    scanf("%d",&k);
    int (*A)[2] = new int[k][2];
    for( i=0; i<k; ++i )
    {
         scanf("%d:%d",&A[i][0],&A[i][1]);
    }
    int basic = n1,combined = n2,unlimited = n3,bas=0,com=0;

    for( i=0; i<k; ++i )
    {
         if(A[i][0]!=0)
         {
                        bas+=A[i][0]; com+=A[i][0];
         }
         if( (A[i][0]==0 && A[i][1]>6) || (A[i][0]!=0 && A[i][1]!=0 ) ) { ++bas; ++com; }
    }
    if ( com>t )
         {
               com-=t; com*=c2;
         }
    bas *= c1;
    basic += bas; combined += com;

    printf("Basic:     %d\n",basic);
    printf("Combined:  %d\n",combined);
    printf("Unlimited: %d\n",unlimited);
    delete [] A;
    return 0;
}

Test:

135 1
220 10 1
300
5
00:05
00:10
00:59
05:00
01:01

Answer:

Basic:     144
Combined:  220
Unlimited: 300

Combined in this test must be 221... because 00:10 gives 1 minute , 00:59 give 1 minute , 05:00 gives 5, 01:01 gives 2...or... 01:01 gives 1 minute or 2 minutes ??

00:10 - 1 minute;
00:59 - 1 minute;
05:00 - 5 minutes;
01:01 - 2 minutes.
All time is 9 minutes.

In this test you are allowed to talk up to 10 minutes per month for free. You talked only 9. So you should pay only monthly fee - 220.

Yes , thanks . I should write
[ else com=0 ]
after
 [ if(com > t){...} ]