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back to boardDiscussion of Problem 1607. TaxiSmth strange I wonder why the solution with Arithmetic progression is impossible. a:=a+b c:=c-d ... ... and several times isn't that equals to a:=a+bx and c:=c-dx ?? Re: Smth strange Because they can stop after a:=a+b c:=c-d ... ... a:=a+b It equals to a:=a+bx c:=c-d(x-1) Edited by author 13.03.2010 01:16 |
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