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back to boardTLE at test#11 Posted by Madhav 17 Jun 2008 17:22 I am getting time limit exceeded using a naive method.How can i write better program.pls some one help me. this is my code #include<iostream> using namespace std; int n; int main(){ cin>>n;int k=1;int i; int *a=new int[n+1]; int *b=new int[n+1]; int *c=new int[n+1]; for(i=1;i<=n;i++){ cin>>a[i]; b[i]=a[i]; } while(1){ for(i=1;i<=n;i++) if(b[i]!=i) break; if(i==n+1){ cout<<k<<endl; break; } for(i=1;i<=n;i++) c[i]=b[i]; for(i=1;i<=n;i++){ b[i]=c[a[i]]; } k++; } return 0; } Re: TLE at test#11 Answer can be up to 10^9, and it is fairly easy to construct such a test - so, try to develop a math solution in O(N) Re: TLE at test#11 Posted by Madhav 19 Jun 2008 23:50 All of them using something like gcd and lcm.Can u tell me the idea. |
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