// PROGRAM 1263 IN C++
# include <iostream.h>
# include <stdio.h>
int main()
{
    int N,M,a[10000];
    double k,l=0;
    cin>>N>>M;
    if (N>=1 && N<=10000 && M>=1 && M<=10000)
    {
        for (int i=0;i<=M-1;i++)
            cin >>a[i];
        for (int p=1;p<=N;p++)
        {
            for (int h=0;h<=M-1;h++)
            {
                if (a[h]==p)
                l++;
            }
            k=(l/M)*100;
            l=0;
            printf ("%.2f",k);
            cout <<'%'<<endl;
        }
    }
    return 0;
}

Edited by author 07.10.2012 21:43

Edited by author 07.10.2012 21:44