How to show 6 digits after the point using double/float variable?

You can do one of the following ways :
1)
fprintf(stdout,"%.6lf ",n) ;
or
printf("%.6lf",n) ;

2)
setprecision( 6 ) ;
cout << n ;
/*
in this way , it won't print out the last zero digits.
for instance :
if n == 0.777 , it will print out "0.777" in stead of "0.777000"
if n == 0.777001 , it will print out exactly 6 digits after the decimal point ( "0.777001" )
*/

Edited by author 25.07.2006 15:55

Thanks!

cout.precision( 6 );
cout << fixed << variable;

what if i want zero digits? using c++, not c

Edited by author 28.08.2010 00:39